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whats the best way to deal with this new "push" on production? on production.
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<blockquote data-quote="paidslave" data-source="post: 512932" data-attributes="member: 10762"><p>I don't think three consecutive days is actually enough. Out of how many days do we work a year? I would guess this is not even close to being accurate assessment of spors. Until UPS can guarantee the exact load everysingle day. IE: same amount of packages and the same amount of stops precisely and the same exact stops the same amount of traffic to a T and make sure that it is sunny out everysingle day of the year like it is on the time study days and driver rides, ect ect, ect, then you cannot hold your end of the bargain there are mucho anomalys! </p><p> </p><p>All wouldn't be equal in my equation, or you may plug in all your number in this equation after your three day ride along. Make sure you click the link on the bottom if you have any questions undertanding my mistakes!</p><p> </p><p> </p><p><strong><span style="font-size: 12px"><span style="color: #003399">Formulas</span></span></strong></p><p> </p><p><strong>From the true anomaly</strong></p><p> </p><p>The eccentric anomaly can be computed from the true anomaly by the formulas</p><p><img src="http://wpcontent.answers.com/math/1/5/a/15a75e1d708f9249625b4a74a62a0d2b.png" alt="" class="fr-fic fr-dii fr-draggable " style="" /> <img src="http://wpcontent.answers.com/math/2/1/0/210a363caad58a003c7337a16abd21c2.png" alt="" class="fr-fic fr-dii fr-draggable " style="" /> hence</p><p><img src="http://wpcontent.answers.com/math/7/0/7/707529133d978fb79067c17f6f72258c.png" alt="" class="fr-fic fr-dii fr-draggable " style="" /> where <img src="http://wpcontent.answers.com/math/c/5/friend/c5f222e62e55cae3b192a3f9d3a90cac.png" alt="" class="fr-fic fr-dii fr-draggable " style="" /> is the angular coordinate of point <span style="font-family: 'Batang'">(<em>X</em>,<em>Y</em>)</span> in <a href="http://www.answers.com/topic/polar-coordinate-system" target="_blank"><u><span style="color: #003399">polar coordinates</span></u></a>.</p><p> </p><p><strong>From the mean anomaly</strong></p><p> </p><p>The eccentric anomaly <em><span style="font-family: 'Batang'">E</span></em> is related to the mean anomaly <em><span style="font-family: 'Batang'">M</span></em> by the formula</p><p><img src="http://wpcontent.answers.com/math/7/4/a/74a295c19e61a931cc179ea9347ea27e.png" alt="" class="fr-fic fr-dii fr-draggable " style="" /> This equation does not have a <a href="http://www.answers.com/topic/closed-form-solution" target="_blank"><u><span style="color: #003399">closed-form solution</span></u></a> for <em><span style="font-family: 'Batang'">E</span></em> given <em><span style="font-family: 'Batang'">M</span></em>. It is usually solved by numerical methods, e.g. <a href="http://www.answers.com/topic/newton-s-method" target="_blank"><u><span style="color: #003399">Newton-Raphson</span></u></a>.</p><p> </p><p><strong>Radius and eccentric anomaly</strong></p><p> </p><p>The radius (distance from the focus of attraction to the orbiting body) is related to the eccentric anomaly by the formula</p><p><img src="http://wpcontent.answers.com/math/7/9/friend/79f9681e45cbba7a8d5dff3ddc23eab9.png" alt="" class="fr-fic fr-dii fr-draggable " style="" /> </p><p> </p><p> </p><p>TIE if this formula doesn't help you understand things that are not real this link might, </p><p> </p><p><a href="http://www.mysticghost.com/GhostHuntingMistakestoAvoid.html" target="_blank"><strong><span style="font-size: 12px">http://www.mysticghost.com/GhostHuntingMistakestoAvoid.html</span></strong></a></p><p> </p><p>I can't wait for my response!</p></blockquote><p></p>
[QUOTE="paidslave, post: 512932, member: 10762"] I don't think three consecutive days is actually enough. Out of how many days do we work a year? I would guess this is not even close to being accurate assessment of spors. Until UPS can guarantee the exact load everysingle day. IE: same amount of packages and the same amount of stops precisely and the same exact stops the same amount of traffic to a T and make sure that it is sunny out everysingle day of the year like it is on the time study days and driver rides, ect ect, ect, then you cannot hold your end of the bargain there are mucho anomalys! All wouldn't be equal in my equation, or you may plug in all your number in this equation after your three day ride along. Make sure you click the link on the bottom if you have any questions undertanding my mistakes! [B][SIZE=3][COLOR=#003399]Formulas[/COLOR][/SIZE][/B] [B]From the true anomaly[/B] The eccentric anomaly can be computed from the true anomaly by the formulas [IMG]http://wpcontent.answers.com/math/1/5/a/15a75e1d708f9249625b4a74a62a0d2b.png[/IMG] [IMG]http://wpcontent.answers.com/math/2/1/0/210a363caad58a003c7337a16abd21c2.png[/IMG] hence [IMG]http://wpcontent.answers.com/math/7/0/7/707529133d978fb79067c17f6f72258c.png[/IMG] where [IMG]http://wpcontent.answers.com/math/c/5/friend/c5f222e62e55cae3b192a3f9d3a90cac.png[/IMG] is the angular coordinate of point [FONT=Batang]([I]X[/I],[I]Y[/I])[/FONT] in [URL="http://www.answers.com/topic/polar-coordinate-system"][U][COLOR=#003399]polar coordinates[/COLOR][/U][/URL]. [B]From the mean anomaly[/B] The eccentric anomaly [I][FONT=Batang]E[/FONT][/I] is related to the mean anomaly [I][FONT=Batang]M[/FONT][/I] by the formula [IMG]http://wpcontent.answers.com/math/7/4/a/74a295c19e61a931cc179ea9347ea27e.png[/IMG] This equation does not have a [URL="http://www.answers.com/topic/closed-form-solution"][U][COLOR=#003399]closed-form solution[/COLOR][/U][/URL] for [I][FONT=Batang]E[/FONT][/I] given [I][FONT=Batang]M[/FONT][/I]. It is usually solved by numerical methods, e.g. [URL="http://www.answers.com/topic/newton-s-method"][U][COLOR=#003399]Newton-Raphson[/COLOR][/U][/URL]. [B]Radius and eccentric anomaly[/B] The radius (distance from the focus of attraction to the orbiting body) is related to the eccentric anomaly by the formula [IMG]http://wpcontent.answers.com/math/7/9/friend/79f9681e45cbba7a8d5dff3ddc23eab9.png[/IMG] TIE if this formula doesn't help you understand things that are not real this link might, [URL="http://www.mysticghost.com/GhostHuntingMistakestoAvoid.html"][B][SIZE=3]http://www.mysticghost.com/GhostHuntingMistakestoAvoid.html[/SIZE][/B][/URL] I can't wait for my response! [/QUOTE]
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whats the best way to deal with this new "push" on production? on production.
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