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<blockquote data-quote="Omega man" data-source="post: 595285" data-attributes="member: 19470"><p><span style="color: #2e2e2e"><span style="font-family: 'Verdana'">If UPS' work measurement was truly fair (based on performance averages) and accurate the following should apply:</span></span></p><p> </p><p> </p><p><span style="color: #2e2e2e"><span style="font-family: 'Verdana'">1. The MEAN value for the entire sample of drivers should be 0.</span></span></p><p><span style="color: #2e2e2e"><span style="font-family: 'Verdana'">The MEAN is the average (adding together all of our results and then dividing it by the sum of the total).</span></span></p><p><span style="color: #2e2e2e"><span style="font-family: 'Verdana'">That is: If you total up the performance results of every driver (+and-) and divide by the total number of drivers it should be 0 (scratch).</span></span></p><p> </p><p><span style="color: #2e2e2e"><span style="font-family: 'Verdana'">2. The MEDIAN value should be very close to the MEAN.</span></span></p><p><span style="color: #2e2e2e"><span style="font-family: 'Verdana'">The MEDIAN is the 'middle value' in your sample.</span></span></p><p><span style="color: #2e2e2e"><span style="font-family: 'Verdana'">For example: if 5 drivers ran -.30under, .30over, .70over, .80over, .90over then the MEDIAN is: .70over</span></span></p><p> </p><p> </p><p><span style="color: #2e2e2e"><span style="font-family: 'Verdana'">3. The MODE value should also be close to 0(scratch).</span></span></p><p><span style="color: #2e2e2e"><span style="font-family: 'Verdana'">The MODE in a list of numbers refers to the value that occurs most frequently.</span></span></p><p><span style="color: #2e2e2e"><span style="font-family: 'Verdana'">That is: There should be more drivers running scratch than anything else.</span></span></p><p> </p><p> </p><p><span style="color: #2e2e2e"><span style="font-family: 'Verdana'">As everyone knows, most of us are running way over-plan. So, how can this be a fair work measurement? It is NOT!</span></span></p></blockquote><p></p>
[QUOTE="Omega man, post: 595285, member: 19470"] [COLOR=#2e2e2e][FONT=Verdana]If UPS' work measurement was truly fair (based on performance averages) and accurate the following should apply:[/FONT][/COLOR] [COLOR=#2e2e2e][FONT=Verdana]1. The MEAN value for the entire sample of drivers should be 0.[/FONT][/COLOR] [COLOR=#2e2e2e][FONT=Verdana]The MEAN is the average (adding together all of our results and then dividing it by the sum of the total).[/FONT][/COLOR] [COLOR=#2e2e2e][FONT=Verdana]That is: If you total up the performance results of every driver (+and-) and divide by the total number of drivers it should be 0 (scratch).[/FONT][/COLOR] [COLOR=#2e2e2e][FONT=Verdana]2. The MEDIAN value should be very close to the MEAN.[/FONT][/COLOR] [COLOR=#2e2e2e][FONT=Verdana]The MEDIAN is the 'middle value' in your sample.[/FONT][/COLOR] [COLOR=#2e2e2e][FONT=Verdana]For example: if 5 drivers ran -.30under, .30over, .70over, .80over, .90over then the MEDIAN is: .70over[/FONT][/COLOR] [COLOR=#2e2e2e][FONT=Verdana]3. The MODE value should also be close to 0(scratch).[/FONT][/COLOR] [COLOR=#2e2e2e][FONT=Verdana]The MODE in a list of numbers refers to the value that occurs most frequently.[/FONT][/COLOR] [COLOR=#2e2e2e][FONT=Verdana]That is: There should be more drivers running scratch than anything else.[/FONT][/COLOR] [COLOR=#2e2e2e][FONT=Verdana]As everyone knows, most of us are running way over-plan. So, how can this be a fair work measurement? It is NOT![/FONT][/COLOR] [/QUOTE]
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